Question: Objects and Accessing values

Given:

 class Inner{
    private int x;
    public void setX(int x){this.x=x;}
  
    public int getX(){return x;}
}

class Outer{
    private Inner y;
    public void setY(Inner y){this.y=y;}
    public Inner getY(){return y;}
}

public class Threado {
    public static void main(String[] args) {
           Outer o = new Outer();
           Inner i = new Inner();
           int n = 10;
           i.setX(n);
           o.setY(i);
           //insert code here
           System.out.println(o.getY().getX());
    }
 }




Which three code fragments, added individually at line  //insert code here, produce the output 100?

A. n = 100;
B. i.setX( 100 );
C. o.getY().setX( 100 );
D. i = new Inner(); i.setX( 100 );
E. o.setY( i ); i = new Inner(); i.setX( 100 );
F. i = new Inner(); i.setX( 100 ); o.setY( i );

Execution:
If put option A in place of //insert code here, we will only get 10 as output
If put option B in place of //insert code here, then we will get 100 as output, as "i" object is set with 100 value and o.getY().getX() is accessing that value.
If put option C in place of //insert code here, then we will get 100 as output, as o.getY() is returning object of Inner class and  setX is setting value into same object.
If put option E in place of //insert code here, then we will get 10 as output, as we are declaring a new object of Inner and setting 100 value in it, but printing object which contain value of previous Inner object.
If put option F in place of //insert code here, then we will get 100 as output as it is updating "o" object(Outer class) and printing value for it

Answer:
B. i.setX( 100 );
F. i = new Inner(); i.setX( 100 ); o.setY( i );
C. o.getY().setX( 100 )